887C - Solution for Cube - CodeForces Solution


brute force implementation *1500

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Python Code:

import sys
input = sys.stdin.readline


def f(a1, b1, c1, d1, e1, f1, g):
    a, b, c, d, e, f = a1.copy(), b1.copy(), c1.copy(), d1.copy(), e1.copy(), f1.copy()
    if len(set(a)) == len(set(b)) == 1:
        if g == 1:
            for i in [c, d, e, f]:
                i[1], i[2] = i[2], i[1]
        elif g == 2:
            d[1], d[2] = d[2], d[1]
            e[0], e[1], e[2], e[3] = e[2], e[3], e[0], e[1]
            f[0], f[3] = f[3], f[0]
        if f[0] == f[1]:
            x = f[0]
            for i1, i2, i3, i4 in [c,d,e,f]:
                if x == i3 == i4:
                    if i1 == i2:
                        x = i1
                    else:
                        break
                else:
                    break
            else:
                return 1

            x = f[0]
            for i1, i2, i3, i4 in [e,d,c,f]:
                if x == i3 == i4:
                    if i1 == i2:
                        x = i1
                    else:
                        break
                else:
                    break
            else:
                return 1
    return 0


w = list(map(int, input().split()))
a1 = w[:4]
a2 = w[4:8]
a3 = w[8:12]
a4 = w[12:16]
a5 = w[16:20]
a6 = [w[21], w[20], w[23], w[22]]

if sum([f(a1, a3, a4, a2, a5, a6, 0), f(a2, a6, a1, a4, a3, a5, 2), f(a4, a5, a1, a2, a3, a6, 1)]) >= 1:
    print('YES')
else:
    print('NO')


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